首页 › python基础教程 › 正文

Python 从url 获取 Host

发布时间:2018-09-26T08:48:46:手机请访问

0

➜  ~ ipython3
Python 3.6.5 |Anaconda custom (x86_64)| (default, Apr 26 2018, 08:42:37)
Type 'copyright', 'credits' or 'license' for more information
IPython 6.1.0 -- An enhanced Interactive Python. Type '?' for help.

In [1]: from urllib.parse import urlparse

In [2]: url = "https://www.168seo.cn/mac-os/24832.html"

In [3]: x = urlparse(url)

In [4]: x
Out[4]: ParseResult(scheme='https', netloc='www.168seo.cn', path='/mac-os/24832.html', params='', query='', fragment='')

In [5]: x.netloc
Out[5]: 'www.168seo.cn'

1

2

3

4

5

6

7

8

9

10

11

12

13

14

15

16

17

➜ ~ ipython3

Python 3.6.5 |Anaconda custom (x86_64)| (default, Apr 26 2018, 08:42:37)

Type 'copyright', 'credits' or 'license' for more information

IPython 6.1.0 -- An enhanced Interactive Python. Type '?' for help.

In [1]: from urllib.parse import urlparse

In [2]: url = "https://www.168seo.cn/mac-os/24832.html"

In [3]: x = urlparse(url)

In [4]: x

Out[4]: ParseResult(scheme='https', netloc='www.168seo.cn', path='/mac-os/24832.html', params='', query='', fragment='')

In [5]: x.netloc

Out[5]: 'www.168seo.cn'

是不是挺方便的，当然你也可以截取，字符串的截取，但是比较麻烦

喜欢 (0)

Mac Flask 报错:RuntimeError: Click will abort further execution because Python 3 was configured to use ASCII as encodin

Python3 file 详解 os.path.dirname/abspath

发表评论点击这里取消回复。