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➜ ~ ipython3 Python 3.6.5 |Anaconda custom (x86_64)| (default, Apr 26 2018, 08:42:37) Type 'copyright', 'credits' or 'license' for more information IPython 6.1.0 -- An enhanced Interactive Python. Type '?' for help. In [1]: from urllib.parse import urlparse In [2]: url = "https://www.168seo.cn/mac-os/24832.html" In [3]: x = urlparse(url) In [4]: x Out[4]: ParseResult(scheme='https', netloc='www.168seo.cn', path='/mac-os/24832.html', params='', query='', fragment='') In [5]: x.netloc Out[5]: 'www.168seo.cn' |
是不是挺方便的,当然你也可以截取,字符串的截取,但是比较麻烦

