两个字典合并，key值部分相同，value 相加-昊天SEO

In [1]:  x = {'a': 1, 'b': 2}
   ...:  y = {'b': 3, 'c': 4}
   ...:

In [2]: {**x,**y}
Out[2]: {'a': 1, 'b': 3, 'c': 4}

In [3]: from collections import Counter

In [4]: dict(Counter(x)+Counter(y))
Out[4]: {'a': 1, 'b': 5, 'c': 4}

In [5]: Counter(x)
Out[5]: Counter({'a': 1, 'b': 2})

In [6]:

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In [1]: x = {'a': 1, 'b': 2}

...: y = {'b': 3, 'c': 4}

...:

In [2]: {**x,**y}

Out[2]: {'a': 1, 'b': 3, 'c': 4}

In [3]: from collections import Counter

In [4]: dict(Counter(x)+Counter(y))

Out[4]: {'a': 1, 'b': 5, 'c': 4}

In [5]: Counter(x)

Out[5]: Counter({'a': 1, 'b': 2})

In [6]:

>>> x = { 'apple': 1, 'banana': 2 }
>>> y = { 'banana': 10, 'pear': 11 }
>>> for k, v in y.items():
...     if k in x.keys():
...         x[k] += v
...     else:
...         x[k] = v
... 
>>> x
{'pear': 11, 'apple': 1, 'banana': 12}

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>>> x = { 'apple': 1, 'banana': 2 }

>>> y = { 'banana': 10, 'pear': 11 }

>>> for k, v in y.items():

... if k in x.keys():

... x[k] += v

... else:

... x[k] = v

...

>>> x

{'pear': 11, 'apple': 1, 'banana': 12}

def union_dict(*objs):
    _keys = set(sum([obj.keys() for obj in objs],[]))
    _total = {}
    for _key in _keys:
        _total[_key] = sum([obj.get(_key,0) for obj in objs])
    return _total

obj1 = {'a':1,'b':2}
obj2 = {'a':1,'b':2}
print union_dict(obj1,obj2)

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def union_dict(*objs):